The diagram above illustrates a wave setup between two fixed ends 4.0m apart. If the speed of the wave is 1.0(ms^{-1}), its wavelength and frequency respectively are
-
A.
1m; 0.25Hz -
B.
2m; 0.25Hz -
C.
2m; 0.50Hz -
D.
4m; 0.50Hz
Correct Answer: Option C
Explanation
For the 4th harmonic, (L = 2lambda)
(4m = 2lambda implies lambda = frac{4m}{2})
=(2m)
Recall, (v = flambda)
(1 = f times 2 implies f = frac{1}{2})
= 0.50Hz