Solve for x in (frac{4x – 6}{3} leq frac{3 + 2x}{2})
-
A.
(x leq 1frac{1}{2}) -
B.
(x leq frac{21}{2}) -
C.
(x geq frac{21}{2}) -
D.
(x geq 1frac{1}{2})
Correct Answer: Option B
Explanation
(frac{4x – 6}{3} leq frac{3 + 2x}{2})
2(4x – 6) (leq) 3(3 + 2x)
8x – 12 (leq) 9 + 6x
8x – 6x (leq) 9 + 12
2x (leq) 21
(x leq frac{21}{2})
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