Simplify (frac{8^2 times 4^n + 1}{2^{2n} times 16})
-
A.
16 -
B.
8 -
C.
4 -
D.
1
Correct Answer: Option C
Explanation
(frac{sqrt{8^2 times 4^{n + 1}}}{2^{2n} times 16})
= (frac{sqrt{2^{3(2)} times 2^{2(n + 1)}}}{2^{2n} times 2^4})
= (frac{sqrt{2^6 times 2^{2n + 2)}}}{2^{2n} + 4})
= (frac{sqrt{2^6 + 2^{2n + 2)}}}{2^{2n} + 4})
= (frac{sqrt{2^{2n + 8}}}{2^{2n} + 4})
= (sqrt{2^{2n + 8} div 2^{2n} + 4})
= (sqrt{2^{2n – 2n} + 8 – 4})
= (sqrt{2^4})
= (sqrt{16})
= 4