PT is a tangent to the circle TYZX. YT = YX and PT is a tangent to the circle TYZX. YT = YX and o. Calculate A. 50o B. 65o C. 85o D. 130o Correct Answer: Option B Explanation XTY = 50o = TXY = (frac{130^o}{2}) = 65o `, props: [‘comment’], data() { return {} }, methods: {} }) {{ reply.posted_by.display_name }}:   {{ reply.created_at }} `, props: [‘comment’, ‘reply’, ‘rate_selection’, ‘token’], data() { return {} }, methods: {} })