Points P and Q respectively 24m north and 7m east point R. What is the bearing of Q from P to the nearest whole degree?
-
A.
16o -
B.
17o -
C.
73o -
D.
106o -
E.
164o
Correct Answer: Option E
Explanation
(tan P = frac{7}{24})
(tan P = 0.2917)
(P = tan^{-1} (0.2917))
= 16.26°
Bearing of Q from P = 180° – 16.26°
= 163.74° (approxeq) 164°