p = (begin{vmatrix} x & 3 & 0 \ 2 & y & 3\ 4 & 2 & 4 end{vmatrix})
Q = (begin{vmatrix} x & 2 & z \ 3 & y & 2\ 0 & 3 & z end{vmatrix})
PQ is equivalent to
Q = (begin{vmatrix} x & 2 & z \ 3 & y & 2\ 0 & 3 & z end{vmatrix})
PQ is equivalent to
-
A.
PPT -
B.
pp-1 -
C.
qp -
D.
pp
Correct Answer: Option A
Explanation
p = (begin{vmatrix} 0 & 3 & 0 \ 2 & 1 & 3\ 4 & 2 & 2 end{vmatrix})
Q = (begin{vmatrix} 0 & 2 & 4 \ 3 & 1 & 2\ 0 & 3 & 2 end{vmatrix}) = pT
pq = ppT