One mole of a compound M(HCO3)2 has a mass of 162g. Calculate the relative atomic mass of M. [H = 1, C =12, O = 16]
-
A.
122 -
B.
101 -
C.
53 -
D.
40
Correct Answer: Option D
Explanation
One of the mole of M(HCO3)2 = 162g; M +(1 + 12 + 16 x 3) x 2 = 162; M +122 = 162,:. M = 162 – 122 = 40g