O is the centre of the circle PQRS. PR and QS intersect at T POR is a diameter, ∠PQT = 42o and ∠QTR = 64o; Find ∠QRT
-
A.
68o -
B.
64o -
C.
42o -
D.
32o -
E.
22o.
Correct Answer: Option A
Explanation
TQR = 90 – 42 = 48o
QRT = 180 – (64 – 48)
    = 180 – 112
    = 68o