make w the subject of the relation (frac{a + bc}{wd + f}) = g

make w the subject of the relation (frac{a + bc}{wd + f}) = g
  • A.
    (frac{a + bc – fg}{dg})
  • B.
    (frac{a – bc + fg}{dg})
  • C.
    (frac{a + bc – f}{dg})
  • D.
    (frac{a + bc – dg}{dg})
Correct Answer: Option A
Explanation

(frac{a + bc}{wd + f}) = g(cross multiply)
a = bc + wdg + fg
wdg = a + bc – fg
w = (frac{a + bc – fg}{dg})

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