Make r subject of the formula given that (frac{x}{r+a}=frac{a}{r})
-
A.
(frac{a^{2}}{(x-a)}) -
B.
(frac{a^{2}}{(x+a)}) -
C.
(frac{a}{x-a}) -
D.
(frac{a}{x+a})
Correct Answer: Option A
Explanation
(frac{x}{r + a} = frac{a}{r})
(implies rx = ar + a^{2})
(rx – ra = a^{2} implies r = frac{a^2}{x – a})