Light of energy 5.0 eV falls on a metal of work function 3.0 eV and electrons are emitted, determine the stopping potential. [electronic charge, e = 1.60 x 108ms-19]
-
A.
1.7V -
B.
2.0V -
C.
8.0V -
D.
15.0V
Correct Answer: Option B
Explanation
(V_8 frac{hf – w_o}{e} = frac{5.0 times 1.60 times 10^{-19} – 3.0 times 1.6 times 10^{-19}}{1.6 times 10^{-19}} = 2.0V)