In the figure, PS = 7cm and RY = 9cm. IF the area of parallelogram PQRS is 56cm2. Find the area of trapezium PQTS
-
A.
56cm2 -
B.
112cm2 -
C.
120cm2 -
D.
176cm2
Correct Answer: Option C
Explanation
From the figure, PS = QR = YT = 7cm
Area of parallelogram PQRS = 56cm
56 = base x height, where base = 7
7 x h = 56cm,
h = (frac{56}{7})
= 8cm
Area of trapezium (frac{1}{2}) (sum of two sides)x height where two sides are QT and PS but QT = QR + RY + YT = 7 +9 + 7 = 23cm
Area of trapezium PQTS = (frac{1}{2})(23 + 7) x 8
(frac{1}{2}) x 30 x 8 = 120cmsq