In the electrolysis of CuSo4(g) using platinum electrode the reaction at the anode is
-
A.
4H+ 4e – 2H2 -
B.
4OH= 4e- + 2H2O + O2 -
C.
2OH – 2e– = 2OH -
D.
2OH– + 2OH = 2H2O + O2
Correct Answer: Option B
Explanation
40H − 4e → 2H2O + O2is the reaction of sun at the anode in the electrolysis of CuSO4 (g) using platinum particles. Option A,C,D are not formed as a result of the equation
There is an explanation video available below.