In the diagram, TS is a tangent to the circle at S. |PR| and In the diagram, TS is a tangent to the circle at S. |PR| and o. Calculate A. 54o B. 44o C. 34o D. 27o Correct Answer: Option A Explanation In the diagram above, x1 = 180o – 117o = 63o(opposite angles of a cyclic quad.) x1 = x2 (base angles of isos. (Delta)) x1 + x2 + (alpha) = 180o (sum of angles of a (Delta) 63o + 63o + (alpha) = 180o (alpha) = 180o – (63 + 63)o = 54o `, props: [‘comment’], data() { return {} }, methods: {} }) {{ reply.posted_by.display_name }}:   {{ reply.created_at }} `, props: [‘comment’, ‘reply’, ‘rate_selection’, ‘token’], data() { return {} }, methods: {} })

In the diagram, TS is a tangent to the circle at S. |PR| and o. Calculate

  • A.
    54o
  • B.
    44o
  • C.
    34o
  • D.
    27o
Correct Answer: Option A
Explanation

In the diagram above, x1 = 180o – 117o = 63o(opposite angles of a cyclic quad.)
x1 = x2 (base angles of isos. (Delta))
x1 + x2 + (alpha) = 180o (sum of angles of a (Delta)
63o + 63o + (alpha) = 180o
(alpha) = 180o – (63 + 63)o
= 54o

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