Answers

In the diagram, PQR is a tangent to the circle QST at Q. If |QT|…

In the diagram, PQR is a tangent to the circle QST at Q. If |QT| = |ST| and ∠SQR = 68°, find ∠PQT.

A.
34^o
B.
48^o
C.
56^o
D.
68^o
E.
73^o

Correct Answer: Option C

Explanation

< STQ = < SQR = 68° (alternate segment)

(therefore) < STQ = 68°

< TQS = (frac{180° – 68°}{2})

= (frac{112}{2} = 56°)

(therefore) < PQT = 180° – (68° + 56°)

= 180° – 124°

= 56°