In the diagram, O is the centre, (bar{RT}) is a diameter, < PQT = 33(^o) and <TOS = 76(^o). Using the diagram, calculate the value of angle PTR.
-
A.
73o -
B.
67o -
C.
57o -
D.
37o
Correct Answer: Option C
Explanation
In the diagram given, < PRT = 3(^o) (Change in same segment)
< TPR = 90(^o) (angle in a semicircle)
Hence, < PTR = 180(^o) – (90 + 33)(^o)
= 180(^o) – 123(^o)
= 57(^o)