In the diagram above PS||RQ, |RQ| = 6.4cm and perpendicular PH = 3.2cm. Find the area of SQR
-
A.
5.12cm2 -
B.
9.60cm2 -
C.
10.24cm2 -
D.
20.48cm2 -
E.
40.96cm2
Correct Answer: Option C
Explanation
Area of a triangle = (frac{1}{2} times b times h)
Area of (Delta) SQR = (frac{1}{2} times 6.4 times 3.2)
= 10.24 cm(^2)