In the diagram above, determine the r.m.s current
-
A.
31A -
B.
48A -
C.
60A -
D.
80A
Correct Answer: Option B
Explanation
Ir.m.s = Vr.m.s/ZBut Z =
√ R2 + XL2 =
√ 42 + 32 =
√ 16 + 9 =
√ 25
∴Ir.m.s = 240/5
= 48.0A
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