In the calibration of an ammeter using faraday’s laws of electrolysis, the ammeter reading is…

In the calibration of an ammeter using faraday’s laws of electrolysis, the ammeter reading is kept constant at 1.2A. If 0.990g of copper is deposited in 40 minutes , the correction to be applied to the ammeter is
  • A.
    0.03A
  • B.
    0.04A
  • C.
    0.05A
  • D.
    0.06A
Correct Answer: Option C
Explanation

From faraday’s law of electrolysis
M = I t Z
0.990 = I x (40 x 60) x 3.3 x 10-4
( implies frac{0.990}{2400 times 3.3 times 10^{-4}} = 1.25A \
text{Thus the correction to be made } = 1.25 – 1.20 = 0.05A )

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In the diagram, ST is parallel to UW, o, o, o and o. Calculate the value of y…
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