In an A.C circuit, the ratio of r.m.s value to peak value of current is
-
A.
2 -
B.
( frac{1}{2} ) -
C.
( frac{1}{sqrt{2}} ) -
D.
( sqrt{2} )
Correct Answer: Option C
Explanation
Irms = ( frac{I_0}{sqrt{2}} )
( text{Therefore } sqrt{2Irms} = I_0 \
frac{Irms}{I_0} = frac{1}{sqrt{2}} )