In a sound wave in air, the adjacent rarefactions and compressions are separated by a distance of 17cm. If the velocity of the sound wave is 340ms-1. Determine the frequency
-
A.
10Hz -
B.
20Hz -
C.
1000Hz -
D.
5780Hz
Correct Answer: Option C
Explanation
(lambda) = 2L
2 x 17 = 34cm
F = (frac{V}{lambda})
= (frac{340}{34 times 10^{-2}})
= 1000Hz