in a nuclear fission process, the mass defect was 1.2 x 10-5kg. Calculate the energy released. [speed of the light in vacuum = c = 3.0 x 108ms-1]
-
A.
1.08 x 1011J -
B.
5.20 x 1011J -
C.
1.08 x 1012J -
D.
2.50 x 1013J
Correct Answer: Option C
Explanation
E – Mec2
E = 1.2 x 10-5 x (3 x 108)2
E = 1.08 x 1012J