In a hydraulic press, the pump piston exerts a pressure of 100 pa on the liquid. what force is exerted in the second piston of cross sectional area 3 m2?
-
A.
300 N -
B.
200 N -
C.
150 N -
D.
100 N
Correct Answer: Option A
Explanation
Thrust = pressure x area = 100 pa x 3 m2 = 300 N