If (y = 6x^3 + 2x^{-2} – x^{-3}), find (frac{mathrm d y}{mathrm d x}).
-
A.
(frac{mathrm d y}{mathrm d x} = 15x^2 – 4x^{-2} – 3x^{-2}) -
B.
(frac{mathrm d y}{mathrm d x} = 6x + 4x^{-1} – 3x^{-4}) -
C.
(frac{mathrm d y}{mathrm d x} = 18x^2 – 4x^{-3} + 3x^{-4}) -
D.
(frac{mathrm d y}{mathrm d x} = 12x^2 + 4x^{-1} – 3x^{-2})
Correct Answer: Option C
Explanation
(y = 6x^3 + 2x^{-2} – x^{-3})
(frac{mathrm d y}{mathrm d x} = 18x^2 – 4x^{-3} + 3x^{-4})
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