If y = 23(_{five}) + 101(_{three}) , find y, leaving your answer in base two

Correct Answer: Option B

Explanation

y = 23(_{five}) + 101(_{three})

23(_{five}) = (2 times 5^1 + 3 times 5^0)

= 13(_{ten})

101(_{three}) = (1 times 3^2 + 0 times 3^1 + 1 times 3^0)

= 10(_{ten})

y(_{ten}) = 13(_{ten}) + 10(_{ten})

= 23(_{ten})

= 10111(_{two})

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