If the force of a charge of 0.2 coulomb in an electric field is 4N, then the electric field intensity of the field is
-
A.
0.8 -
B.
0.8N/C -
C.
20.0N/C -
D.
4.2N/C
Correct Answer: Option C
Explanation
Field intensity = (frac{force}{charge})
(frac{4}{0.2}) = 20N/C