If the cost of electricity required to discharge 10g of an ion X(^{3+}) is N20.00, how much would it cost to discharge 6g of ion Y(^{2+})?
[1 faraday = 96,500C, atomic masses are X = 27, Y = 24]-
A.
N10.00 -
B.
N6.00 -
C.
N20.00 -
D.
N9.00
Correct Answer: Option D
Explanation
X(^{3+}) + 3e(^-) (to) X
3F = 27g
xF = 10g
(frac{x}{3} = frac{10}{27} implies x = frac{10}{9} F)
(frac{10}{9})F (equiv) N20.00
1F is equivalent to x
(frac{1}{frac{10}{9}} = frac{x}{20})
(frac{9}{10} = frac{x}{20} implies x = N18.00)
1F is equivalent to N18.00.
Y(^{2+}) + 2e(^-) (to) Y
2F = 24g
xF = 6g
x = (frac{6 times 2}{24} = frac{1}{2} F)
1F = N18.00
(frac{1}{2})F = (frac{1}{2} times N18.00)
= N9.00
There is an explanation video available below.