If sin 3y = cos 2y and 0o (leq) 90o, find the value of y

If sin 3y = cos 2y and 0o (leq) 90o, find the value of y
  • A.
    18o
  • B.
    36o
  • C.
    54o
  • D.
    90o
Correct Answer: Option A
Explanation

sin 3y = cos 2y, but sin (theta) = cos(90 – (theta))
sin 3y = cos(90 – 3y)
cos(90 – 3y) = cos 2y
90 – 3y = 2y
5y = 90
y = (frac{90}{5})
y = 18o

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