If sin 3y = cos 2y and 0o (leq) 90o, find the value of y
-
A.
18o -
B.
36o -
C.
54o -
D.
90o
Correct Answer: Option A
Explanation
sin 3y = cos 2y, but sin (theta) = cos(90 – (theta))
sin 3y = cos(90 – 3y)
cos(90 – 3y) = cos 2y
90 – 3y = 2y
5y = 90
y = (frac{90}{5})
y = 18o