If log 2 = x, log 3 = y and log 7 = z, find, in terms of x, y and z, the value of log ((frac{28}{3}))
-
A.
2x + y – z -
B.
2x + x – y -
C.
x + y – 2x -
D.
x + x – y
Correct Answer: Option B
Explanation
log ((frac{28}{3}) = log (frac{7 times 4}{3}))
= log 7 + log 4 – log 3
log 7 + log 22 – log 3 = log 7 + 2 – log 3
= x + 2x – y
= 2x + x – y