If in a simple pendulum experiment the length of the inextensible string is increased by a factor of four, its period is increased by a factor of
-
A.
4 -
B.
(frac{pi}{2}) -
C.
(frac{1}{4}) -
D.
2(pi) -
E.
2
Correct Answer: Option E
Explanation
In simple pendulum, T = 2(pi)(sqrtfrac{L}{g})
(frac{T_2}{T_1}) = (sqrtfrac{L_1}{L_2}) but, L2 = 4L1
(frac{T_2}{T_1}) = (sqrtfrac{L_1}{4L_1})
T2 = 4T1