If (f(x) = 2x^{2} – 3x – 1), find the value of x for which f(x) is minimum.
-
A.
(frac{3}{2}) -
B.
(frac{4}{3}) -
C.
(frac{3}{4}) -
D.
(frac{2}{3})
Correct Answer: Option C
Explanation
(y = 2x^{2} – 3x – 1)
(frac{mathrm d y}{mathrm d x} = 4x – 3 = 0) (At turning point)
(4x = 3 implies x = frac{3}{4})