If (frac{9^{2x-1}}{27^{x+1}} = 1), find the value of x.
-
A.
8 -
B.
5 -
C.
3 -
D.
2
Correct Answer: Option B
Explanation
(frac{9^{2x – 1}}{27^{x + 1}} = 1)
(implies 9^{2x – 1} = 27^{x + 1})
((3^{2})^{2x – 1} = (3^{3})^{x + 1})
(2(2x – 1) = 3(x + 1) implies 4x – 2 = 3x + 3)
(4x – 3x = 3 + 2 implies x = 5)