If a wire 30 cm long is extended to 30.5 cm by a force of 300 N. find the strain energy of wire
-
A.
0.75 J -
B.
7.50 J -
C.
75.00 J -
D.
750.00 J
Correct Answer: Option A
Explanation
Energy stored in a stretched wire (strain energy)
= average force x extension
= (1)/2 Fe
= (1)/2 x 300 N (30.5 – 30.0) x 10-2 m
= (300)/2 x 0.5 x 10-2 = 0.75J