If a load of mass 10N stretched a cord by 1.2cm, what is the total work done?
-
A.
6.0 x 10-2J -
B.
7.6 x 10-2J -
C.
1.8 x 10-2J -
D.
6.6 x 10-2J
Correct Answer: Option A
Explanation
Work done on a stretched cord
= Average force x extension
= (10 + 0)/2 x 1.2 x 10-2
= 6.0 x 10-2J