If a body mass 5kg is thrown vertically upwards with velocity u,at what height will the potential energy equal to the kinetic energy?
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A.
h =(u)2/g -
B.
h = (u)2/4g -
C.
h = (2u)2/g -
D.
h = (u)2/2g
Correct Answer: Option B
Explanation
From V2 = U2 + 2as
O = U 2 – 2gH, since at maximum height H, the final velocity, v = O.
∴ H = (U)2/2g
PE = KE at (1)/2 H = (U)2/2g x (1)/2 = U2 4g