If 2 log x (3(frac{3}{8})) = 6, find the value of x
-
A.
(frac{3}{2}) -
B.
(frac{4}{3}) -
C.
(frac{2}{3}) -
D.
(frac{1}{2})
Correct Answer: Option A
Explanation
2 log x (3(frac{3}{8})) = 6(divide both sides by 2)
(frac{2 log_x(3 frac{3}{8})}{2} = frac{6}{2})
(log_x frac{27}{8} = 3)
(frac{27}{8} = x^3)
(x^3 = frac{27}{8})
x = (sqrt{frac{27}{8}})
= ((frac{27}{8}))(frac{1}{3})
= (frac{(3^3)^{frac{1}{3}}}{(2^3)^{frac{1}{3}}})
= (frac{3}{2})