How many moles of oxygen would contain 1.204 x 1024 molecules?
[Avogadro’s constant (NA) = 6.02 x 1023]
[Avogadro’s constant (NA) = 6.02 x 1023]
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A.
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B.
2 -
C.
3 -
D.
4
Correct Answer: Option B
Explanation
6.02 x 1023 molecules is 1mole
1.204 x 1024 molecules will be……
(frac{1.204 times 10^24 times 1}{6.02 times 10^23})
(frac{1.204 times 10}{6.02}) = (frac{12.04}{6.02}) = 2moles