How many grams of water at 17oC must be added to 42g of ice at 0oC to melt the ice completely? [specific latent heat of fusion of ice = 3.4 x 105Jkg-1, specific heat capacity of water = 4200Jkg-1k-1]
-
A.
200g -
B.
300g -
C.
320g -
D.
400g
Correct Answer: Option A
Explanation
Heat lost = Heat gained
mc(theta) = mL
m x 4200 x 17 = 42 x 3.4 x 105
therefore, m = 200g