Given that sin (5x – 28)o = cos (3x – 50)o,0 Given that sin (5x – 28)o = cos (3x – 50)o,0 o, find the value of x A. 14o B. 21o C. 32o D. 39o Correct Answer: Option B Explanation Sin (5x – 28)o = cos (3x – 50)o Since by the trigonometry relation Sin(5x – 28)o = cos[90 – (5x – 28)]o Hence cos(3x – 50)o = cos[90 – (5x – 28)]o 3x – 50 = 90 – (5x-28) 3x – 50 = 90 – 5x + 28 3x + 5x = 90 + 28 + 50 8x = 168 (x = frac{168}{8}=21^{circ}) `, props: [‘comment’], data() { return {} }, methods: {} }) {{ reply.posted_by.display_name }}:   {{ reply.created_at }}

Given that sin (5x – 28)o = cos (3x – 50)o,0 o, find the value of x
  • A.
    14o
  • B.
    21o
  • C.
    32o
  • D.
    39o
Correct Answer: Option B
Explanation

Sin (5x – 28)o = cos (3x – 50)o
Since by the trigonometry relation
Sin(5x – 28)o = cos[90 – (5x – 28)]o
Hence cos(3x – 50)o = cos[90 – (5x – 28)]o
3x – 50 = 90 – (5x-28)
3x – 50 = 90 – 5x + 28
3x + 5x = 90 + 28 + 50
8x = 168
(x = frac{168}{8}=21^{circ})

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