Given that (frac{1}{2} log_{10} P = 1), find the value of P.
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A.
104 -
B.
103 -
C.
102 -
D.
101 -
E.
10-1
Correct Answer: Option C
Explanation
(frac{1}{2} log_{10} P = 1)
(log_{10} P^{frac{1}{2}} = 1)
(P^{frac{1}{2}} = 10^{1})
(implies P = 10^{2})
Given that (frac{1}{2} log_{10} P = 1), find the value of P.
(frac{1}{2} log_{10} P = 1)
(log_{10} P^{frac{1}{2}} = 1)
(P^{frac{1}{2}} = 10^{1})
(implies P = 10^{2})