Given that (81times 2^{2n-2} = K, find sqrt{K})
-
A.
(4.5times 2^{n}) -
B.
(4.5times 2^{2n}) -
C.
(9times 2^{n-1}) -
D.
(9times 2^{2n})
Correct Answer: Option C
Explanation
(K = 81 times 2^{2n – 2})
(sqrt{K} = sqrt{81 times 2^{2n – 2}})
= (9 times 2^{n – 1})