From a point R, 300m north of P, man walks eastward to a place Q which is 600m from P. Find the bearing of P from Q, correct to the nearest degreeee
-
A.
026o -
B.
045o -
C.
210o -
D.
240o
Correct Answer: Option D
Explanation
(costheta = frac{adj}{hyp}=frac{300}{600}=frac{1}{2}\
theta = cos^{-1}(0.5000)=60^{circ})
The bearing of P from (Q = theta + 180 = 60 + 180 = 240^{circ})