Find the value of p for which (x^{2} – x + p) becomes a perfect square.
-
A.
(-frac{1}{2}) -
B.
(frac{1}{4}) -
C.
(frac{1}{2}) -
D.
(1)
Correct Answer: Option B
Explanation
The equation (ax^{2} + bx + c) is a perfect square if (b^{2} = 4ac).
(x^{2} – x + p)
((-1)^{2} = 4(1)(p))
(1 = 4p implies p = frac{1}{4})