Find the value of (frac{tan 60^o – tan 30^o}{tan 60^o + tan 30^o})
-
A.
(frac{4}{sqrt{3}}) -
B.
(frac{2}{sqrt{3}}) -
C.
1 -
D.
(frac{1}{2})
Correct Answer: Option D
Explanation
(frac{tan 60^o – tan 30^o}{tan 60^o + tan 30^o}= frac{sqrt{3}-frac{1}{sqrt{3}}}{sqrt{3}+frac{1}{sqrt{3}}}\
=left(frac{sqrt{3}sqrt{3}-1}{sqrt{3}}right)div left(frac{sqrt{3}sqrt{3}+1}{sqrt{3}}right)\
=frac{(3-1)}{(3+1)}\
=frac{2}{4}=frac{1}{2})