Find the sum to infinity of the series
(frac{1}{4}), (frac{1}{8}), (frac{1}{16}),……….
(frac{1}{4}), (frac{1}{8}), (frac{1}{16}),……….
-
A.
(frac{1}{2}) -
B.
(frac{3}{5}) -
C.
(frac{-1}{5}) -
D.
(frac{73}{12})
Correct Answer: Option A
Explanation
Sum to infinity
∑ = arn − 1
= (frac{a}{1}) − r
a = (frac{1}{4})
r = (frac{1}{8}) ÷ (frac{1}{4})
r = (frac{1}{s}) × (frac{4}{1})
= (frac{1}{2})
S = (frac{1 div 4}{1}) − (frac{1}{2})
= (frac{1}{4}) ÷ (frac{1}{2})
= (frac{1}{4}) × (frac{2}{1})
= (frac{1}{2})
There is an explanation video available below.