Find the locus of a particle which moves in the first quadrant so that it is equidistant from the lines x = 0 and y = 0 (where k is a constant)
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A.
x + y = 0 -
B.
x – y = 0 -
C.
x + y + k = 0 -
D.
x – y – k = 0
Correct Answer: Option B
Explanation
Locus of a particle which moves in the first quadrant so that it is equidistant from the lines
X = 0 and Y = 0 and x = 0 and y = 0 are the x and y axes is the lines bisecting the angle between x and y axes