Find a factor which is common to all three binomial expressions 4a2 – 9b2, 8a3 + 27b3, (4a + 6b)2
-
A.
4a + 6b -
B.
4a – 6b -
C.
2a + 3b -
D.
2a – 3b -
E.
none
Correct Answer: Option C
Explanation
4a2 – 9b2, 8a3 + 27b3, (4a + 6b)2 = (2a + 3b)(2a – 3b)
8a3 + 27b3 = (2a)3 + (3b)3
= (2a + 3b)(4a – 6ab = 9a2)
(4a + 6b)2 = 2(2a + 3b)2