During the electrolysis of copper (II) tetraoxosulphate (VI) solution, a steady current of 4.0 x 10(^2) A flowing for one hour liberated 0.48 g of copper. Calculate the mass of copper liberated by one coulomb of charge.
Explanation
M = Zit
Z = (frac{M}{It})
= (frac{0.48 times 10^{-3}}{4 times 10^2 times 3600}) = 3.3 x 10(^{-10})kgc(^{-1})