Consider the following reaction equation:
SO42-(aq) + 2H+(aq) + ye– (to) SO42-(aq) + H2O(1).
The value of y in the equation is
SO42-(aq) + 2H+(aq) + ye– (to) SO42-(aq) + H2O(1).
The value of y in the equation is
-
A.
2 -
B.
3 -
C.
4 -
D.
6
Correct Answer: Option A
Explanation
from the reaction, the total charge on the left side = The total charge on the right side
-2 + 2 + y = -2 : y = -2 : y = 2