Consider the following reaction equation:
C2H4(g) + 3O2(g) (to) 2CO2(g) + 2H2O(g)
The volume of CO2(g) produced at s.t.p when 0.05 moles of C2H4(g) was burnt in O2(g) is
[Molar Volume of gas = 22.4dm3
C2H4(g) + 3O2(g) (to) 2CO2(g) + 2H2O(g)
The volume of CO2(g) produced at s.t.p when 0.05 moles of C2H4(g) was burnt in O2(g) is
[Molar Volume of gas = 22.4dm3
-
A.
1.12dm3 -
B.
2.24dm3 -
C.
3.72dm3 -
D.
4.48dm3
Correct Answer: Option A
Explanation
(frac{text{volume}}{text{molar volume}}) = 0.05
= (frac{text{volume}}{22.4}) = 0.05 x 22.4 = 1.12dm3